14112420311433 has 8 divisors (see below), whose sum is σ = 18816692963968. Its totient is φ = 9408213933264.

The previous prime is 14112420311387. The next prime is 14112420311441. The reversal of 14112420311433 is 33411302421141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 14112420311433 - 2⁸ = 14112420311177 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14112420311433.

It is not an unprimeable number, because it can be changed into a prime (14112420311453) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16069585 + ... + 16925022.

It is an arithmetic number, because the mean of its divisors is an integer number (2352086620496).

Almost surely, 2^{14112420311433} is an apocalyptic number.

It is an amenable number.

14112420311433 is a deficient number, since it is larger than the sum of its proper divisors (4704272652535).

14112420311433 is a wasteful number, since it uses less digits than its factorization.

14112420311433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33137183.

The product of its (nonzero) digits is 6912, while the sum is 30.

Adding to 14112420311433 its reverse (33411302421141), we get a palindrome (47523722732574).

The spelling of 14112420311433 in words is "fourteen trillion, one hundred twelve billion, four hundred twenty million, three hundred eleven thousand, four hundred thirty-three".