Base | Representation |
---|---|
bin | 1100110101011101001100… |
… | …1110101100111101010101 |
3 | 1211222010212011222222121200 |
4 | 3031113103032230331111 |
5 | 3322204410410222401 |
6 | 50003110453103113 |
7 | 2654411121526032 |
oct | 315272316547525 |
9 | 54863764888550 |
10 | 14112511414101 |
11 | 455109a865341 |
12 | 16bb123627a99 |
13 | 7b4a5b8486a9 |
14 | 36b098dd4389 |
15 | 197173728686 |
hex | cd5d33acf55 |
14112511414101 has 48 divisors (see below), whose sum is σ = 21397340520192. Its totient is φ = 8945885203200.
The previous prime is 14112511414093. The next prime is 14112511414163. The reversal of 14112511414101 is 10141411521141.
14112511414101 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 2 + 511 + 4 + 141 + 0 + 1 = 666.
It is not a de Polignac number, because 14112511414101 - 23 = 14112511414093 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14112511414171) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 92579736 + ... + 92732046.
It is an arithmetic number, because the mean of its divisors is an integer number (445777927504).
Almost surely, 214112511414101 is an apocalyptic number.
It is an amenable number.
14112511414101 is a deficient number, since it is larger than the sum of its proper divisors (7284829106091).
14112511414101 is a wasteful number, since it uses less digits than its factorization.
14112511414101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 154994 (or 154991 counting only the distinct ones).
The product of its (nonzero) digits is 640, while the sum is 27.
Adding to 14112511414101 its reverse (10141411521141), we get a palindrome (24253922935242).
The spelling of 14112511414101 in words is "fourteen trillion, one hundred twelve billion, five hundred eleven million, four hundred fourteen thousand, one hundred one".
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