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14112545214550 = 252282250904291
BaseRepresentation
bin1100110101011101010100…
…1111101001000001010110
31211222010221112121020010011
43031113111033221001112
53322204443033331200
650003114101350434
72654412012033436
oct315272517510126
954863845536104
1014112545214550
1145511079510a2
1216bb132a0841a
137b4a65851463
1436b09d6b22c6
151971766a35ba
hexcd5d53e9056

14112545214550 has 12 divisors (see below), whose sum is σ = 26249334099156. Its totient is φ = 5645018085800.

The previous prime is 14112545214499. The next prime is 14112545214679. The reversal of 14112545214550 is 5541254521141.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 141125452096 + ... + 141125452195.

It is an arithmetic number, because the mean of its divisors is an integer number (2187444508263).

Almost surely, 214112545214550 is an apocalyptic number.

14112545214550 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14112545214550 is a deficient number, since it is larger than the sum of its proper divisors (12136788884606).

14112545214550 is a wasteful number, since it uses less digits than its factorization.

14112545214550 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 282250904303 (or 282250904298 counting only the distinct ones).

The product of its (nonzero) digits is 160000, while the sum is 40.

Adding to 14112545214550 its reverse (5541254521141), we get a palindrome (19653799735691).

The spelling of 14112545214550 in words is "fourteen trillion, one hundred twelve billion, five hundred forty-five million, two hundred fourteen thousand, five hundred fifty".

Divisors: 1 2 5 10 25 50 282250904291 564501808582 1411254521455 2822509042910 7056272607275 14112545214550