Base | Representation |
---|---|
bin | 1000001101110000000… |
… | …0001111011100001010 |
3 | 111111021121000001010212 |
4 | 2003130000033130022 |
5 | 4303013240113414 |
6 | 144500105441122 |
7 | 13124222146202 |
oct | 2033400173412 |
9 | 444247001125 |
10 | 141130004234 |
11 | 5494223203a |
12 | 234281a01a2 |
13 | 10401a1985b |
14 | 6b8b73b402 |
15 | 3a1003283e |
hex | 20dc00f70a |
141130004234 has 4 divisors (see below), whose sum is σ = 211695006354. Its totient is φ = 70565002116.
The previous prime is 141130004231. The next prime is 141130004299. The reversal of 141130004234 is 432400031141.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 432400031141 = 13 ⋅33261540857.
It can be written as a sum of positive squares in only one way, i.e., 108204813025 + 32925191209 = 328945^2 + 181453^2 .
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (141130004231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 35282501057 + ... + 35282501060.
Almost surely, 2141130004234 is an apocalyptic number.
141130004234 is a deficient number, since it is larger than the sum of its proper divisors (70565002120).
141130004234 is an equidigital number, since it uses as much as digits as its factorization.
141130004234 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70565002119.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 141130004234 its reverse (432400031141), we get a palindrome (573530035375).
The spelling of 141130004234 in words is "one hundred forty-one billion, one hundred thirty million, four thousand, two hundred thirty-four".
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