141130031243 has 4 divisors (see below), whose sum is σ = 145682612928. Its totient is φ = 136577449560.

The previous prime is 141130031221. The next prime is 141130031257. The reversal of 141130031243 is 342130031141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 342130031141 = 5237 ⋅65329393.

It is a cyclic number.

It is not a de Polignac number, because 141130031243 - 2³² = 136835063947 is a prime.

It is a super-2 number, since 2×141130031243² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (141130031213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2276290796 + ... + 2276290857.

It is an arithmetic number, because the mean of its divisors is an integer number (36420653232).

Almost surely, 2^141130031243 is an apocalyptic number.

141130031243 is a deficient number, since it is larger than the sum of its proper divisors (4552581685).

141130031243 is an equidigital number, since it uses as much as digits as its factorization.

141130031243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4552581684.

The product of its (nonzero) digits is 864, while the sum is 23.

Adding to 141130031243 its reverse (342130031141), we get a palindrome (483260062384).

The spelling of 141130031243 in words is "one hundred forty-one billion, one hundred thirty million, thirty-one thousand, two hundred forty-three".