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141130124233253 is a prime number
BaseRepresentation
bin100000000101101101101010…
…111011000000101000100101
3200111200220112000100220200122
4200011231222323000220211
5121444233443300431003
61220054141203251325
741504213020544411
oct4005555273005045
9614626460326618
10141130124233253
1140a71a49969581
12139b3b69079b45
13609968a52a75c
1426bca3d4dbd41
15114b1b9956238
hex805b6aec0a25

141130124233253 has 2 divisors, whose sum is σ = 141130124233254. Its totient is φ = 141130124233252.

The previous prime is 141130124233199. The next prime is 141130124233321. The reversal of 141130124233253 is 352332421031141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131294518057924 + 9835606175329 = 11458382^2 + 3136177^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141130124233253 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141130124230253) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565062116626 + 70565062116627.

It is an arithmetic number, because the mean of its divisors is an integer number (70565062116627).

Almost surely, 2141130124233253 is an apocalyptic number.

It is an amenable number.

141130124233253 is a deficient number, since it is larger than the sum of its proper divisors (1).

141130124233253 is an equidigital number, since it uses as much as digits as its factorization.

141130124233253 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 35.

Adding to 141130124233253 its reverse (352332421031141), we get a palindrome (493462545264394).

The spelling of 141130124233253 in words is "one hundred forty-one trillion, one hundred thirty billion, one hundred twenty-four million, two hundred thirty-three thousand, two hundred fifty-three".