Base | Representation |
---|---|
bin | 1100110101011111000111… |
… | …0100001010110001011001 |
3 | 1211222012011221120002111222 |
4 | 3031113301310022301121 |
5 | 3322211433241131100 |
6 | 50003233423301425 |
7 | 2654426622242000 |
oct | 315276164126131 |
9 | 54865157502458 |
10 | 14113024552025 |
11 | 4551333485473 |
12 | 16bb24744a875 |
13 | 7b4b10c506b9 |
14 | 36b107209c37 |
15 | 1971a37d9485 |
hex | cd5f1d0ac59 |
14113024552025 has 192 divisors, whose sum is σ = 22311371980800. Its totient is φ = 8815642214400.
The previous prime is 14113024552009. The next prime is 14113024552049. The reversal of 14113024552025 is 52025542031141.
It is not a de Polignac number, because 14113024552025 - 24 = 14113024552009 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 759041129 + ... + 759059721.
It is an arithmetic number, because the mean of its divisors is an integer number (116205062400).
Almost surely, 214113024552025 is an apocalyptic number.
It is an amenable number.
14113024552025 is a deficient number, since it is larger than the sum of its proper divisors (8198347428775).
14113024552025 is a wasteful number, since it uses less digits than its factorization.
14113024552025 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18809 (or 18790 counting only the distinct ones).
The product of its (nonzero) digits is 48000, while the sum is 35.
Adding to 14113024552025 its reverse (52025542031141), we get a palindrome (66138566583166).
The spelling of 14113024552025 in words is "fourteen trillion, one hundred thirteen billion, twenty-four million, five hundred fifty-two thousand, twenty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •