14113024552139 has 2 divisors, whose sum is σ = 14113024552140. Its totient is φ = 14113024552138.

The previous prime is 14113024552117. The next prime is 14113024552141. The reversal of 14113024552139 is 93125542031141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14113024552139 - 2¹² = 14113024548043 is a prime.

Together with 14113024552141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14113024552096 and 14113024552105.

It is not a weakly prime, because it can be changed into another prime (14113024552199) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056512276069 + 7056512276070.

It is an arithmetic number, because the mean of its divisors is an integer number (7056512276070).

Almost surely, 2^{14113024552139} is an apocalyptic number.

14113024552139 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113024552139 is an equidigital number, since it uses as much as digits as its factorization.

14113024552139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 129600, while the sum is 41.

The spelling of 14113024552139 in words is "fourteen trillion, one hundred thirteen billion, twenty-four million, five hundred fifty-two thousand, one hundred thirty-nine".