14113031153143 has 4 divisors (see below), whose sum is σ = 15198648934168. Its totient is φ = 13027413372120.

The previous prime is 14113031153141. The next prime is 14113031153147. The reversal of 14113031153143 is 34135113031141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14113031153143 - 2¹ = 14113031153141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113031153141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542808890493 + ... + 542808890518.

It is an arithmetic number, because the mean of its divisors is an integer number (3799662233542).

Almost surely, 2^{14113031153143} is an apocalyptic number.

14113031153143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14113031153143 is a deficient number, since it is larger than the sum of its proper divisors (1085617781025).

14113031153143 is a wasteful number, since it uses less digits than its factorization.

14113031153143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1085617781024.

The product of its (nonzero) digits is 6480, while the sum is 31.

Adding to 14113031153143 its reverse (34135113031141), we get a palindrome (48248144184284).

The spelling of 14113031153143 in words is "fourteen trillion, one hundred thirteen billion, thirty-one million, one hundred fifty-three thousand, one hundred forty-three".