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141131212204344 = 2335880467175181
BaseRepresentation
bin100000000101101110101011…
…110001010010100100111000
3200111201000022211120120110020
4200011232223301102210320
5121444243210311014334
61220054441150250440
741504252001260655
oct4005565361224470
9614630284516406
10141131212204344
1140a7245800833a
12139b42114b6a20
136099801a5922b
1426bcb03bc8c2c
15114b230212e49
hex805babc52938

141131212204344 has 16 divisors (see below), whose sum is σ = 352828030510920. Its totient is φ = 47043737401440.

The previous prime is 141131212204331. The next prime is 141131212204393. The reversal of 141131212204344 is 443402212131141.

It is a super-2 number, since 2×1411312122043442 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2940233587567 + ... + 2940233587614.

Almost surely, 2141131212204344 is an apocalyptic number.

It is an amenable number.

141131212204344 is an abundant number, since it is smaller than the sum of its proper divisors (211696818306576).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141131212204344 is a wasteful number, since it uses less digits than its factorization.

141131212204344 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5880467175190 (or 5880467175186 counting only the distinct ones).

The product of its (nonzero) digits is 18432, while the sum is 33.

Adding to 141131212204344 its reverse (443402212131141), we get a palindrome (584533424335485).

The spelling of 141131212204344 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred twelve million, two hundred four thousand, three hundred forty-four".

Divisors: 1 2 3 4 6 8 12 24 5880467175181 11760934350362 17641401525543 23521868700724 35282803051086 47043737401448 70565606102172 141131212204344