Base | Representation |
---|---|
bin | 1100110101011111100001… |
… | …0110100110011001111100 |
3 | 1211222012110120221220001120 |
4 | 3031113320112212121330 |
5 | 3322212144331211104 |
6 | 50003252342310540 |
7 | 2654432423501052 |
oct | 315277026463174 |
9 | 54865416856046 |
10 | 14113134241404 |
11 | 455138a394750 |
12 | 16bb278128450 |
13 | 7b4b2a8a7563 |
14 | 36b117a001d2 |
15 | 1971ad254cd9 |
hex | cd5f85a667c |
14113134241404 has 48 divisors (see below), whose sum is σ = 37083191448576. Its totient is φ = 4138749043200.
The previous prime is 14113134241403. The next prime is 14113134241411. The reversal of 14113134241404 is 40414243131141.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14113134241403) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1724474677 + ... + 1724482860.
It is an arithmetic number, because the mean of its divisors is an integer number (772566488512).
Almost surely, 214113134241404 is an apocalyptic number.
It is an amenable number.
14113134241404 is an abundant number, since it is smaller than the sum of its proper divisors (22970057207172).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14113134241404 is a wasteful number, since it uses less digits than its factorization.
14113134241404 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3448957586 (or 3448957584 counting only the distinct ones).
The product of its (nonzero) digits is 18432, while the sum is 33.
Adding to 14113134241404 its reverse (40414243131141), we get a palindrome (54527377372545).
The spelling of 14113134241404 in words is "fourteen trillion, one hundred thirteen billion, one hundred thirty-four million, two hundred forty-one thousand, four hundred four".
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