141131401131271 has 2 divisors, whose sum is σ = 141131401131272. Its totient is φ = 141131401131270.

The previous prime is 141131401131263. The next prime is 141131401131373. The reversal of 141131401131271 is 172131104131141.

141131401131271 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141131401131271 - 2³ = 141131401131263 is a prime.

It is a super-3 number, since 3×141131401131271³ (a number of 43 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141131401131211) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565700565635 + 70565700565636.

It is an arithmetic number, because the mean of its divisors is an integer number (70565700565636).

Almost surely, 2^{141131401131271} is an apocalyptic number.

141131401131271 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131401131271 is an equidigital number, since it uses as much as digits as its factorization.

141131401131271 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 31.

The spelling of 141131401131271 in words is "one hundred forty-one trillion, one hundred thirty-one billion, four hundred one million, one hundred thirty-one thousand, two hundred seventy-one".