14113140245503 has 8 divisors (see below), whose sum is σ = 15265721339568. Its totient is φ = 12970124140224.

The previous prime is 14113140245473. The next prime is 14113140245531. The reversal of 14113140245503 is 30554204131141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 14113140245503 - 2⁵ = 14113140245471 is a prime.

It is a super-2 number, since 2×14113140245503² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113180245503) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2391244126 + ... + 2391250027.

It is an arithmetic number, because the mean of its divisors is an integer number (1908215167446).

Almost surely, 2^{14113140245503} is an apocalyptic number.

14113140245503 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14113140245503 is a deficient number, since it is larger than the sum of its proper divisors (1152581094065).

14113140245503 is a wasteful number, since it uses less digits than its factorization.

14113140245503 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4782494393.

The product of its (nonzero) digits is 28800, while the sum is 34.

Adding to 14113140245503 its reverse (30554204131141), we get a palindrome (44667344376644).

The spelling of 14113140245503 in words is "fourteen trillion, one hundred thirteen billion, one hundred forty million, two hundred forty-five thousand, five hundred three".