Base | Representation |
---|---|
bin | 1100110101011111100011… |
… | …0110001001101101000010 |
3 | 1211222012111011112002210121 |
4 | 3031113320312021231002 |
5 | 3322212203440344300 |
6 | 50003253235450454 |
7 | 2654432554006642 |
oct | 315277066115502 |
9 | 54865434462717 |
10 | 14113142512450 |
11 | 4551394023923 |
12 | 16bb27aa56a2a |
13 | 7b4b2c512177 |
14 | 36b118b54522 |
15 | 1971add3a81a |
hex | cd5f8d89b42 |
14113142512450 has 48 divisors (see below), whose sum is σ = 26518329682560. Its totient is φ = 5587913520000.
The previous prime is 14113142512439. The next prime is 14113142512453. The reversal of 14113142512450 is 5421524131141.
It is not an unprimeable number, because it can be changed into a prime (14113142512453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1204590 + ... + 5447689.
It is an arithmetic number, because the mean of its divisors is an integer number (552465201720).
Almost surely, 214113142512450 is an apocalyptic number.
14113142512450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
14113142512450 is a deficient number, since it is larger than the sum of its proper divisors (12405187170110).
14113142512450 is a wasteful number, since it uses less digits than its factorization.
14113142512450 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6652723 (or 6652718 counting only the distinct ones).
The product of its (nonzero) digits is 19200, while the sum is 34.
Adding to 14113142512450 its reverse (5421524131141), we get a palindrome (19534666643591).
The spelling of 14113142512450 in words is "fourteen trillion, one hundred thirteen billion, one hundred forty-two million, five hundred twelve thousand, four hundred fifty".
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