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14113202433 = 311433987697
BaseRepresentation
bin11010010010011011…
…00110000100000001
31100102120110222010020
431021031212010001
5212400434434213
610252234524053
71006511145531
oct151115460401
940376428106
1014113202433
115a92597970
12289a596629
13143bbc5a75
1497c5434c1
15579044923
hex349366101

14113202433 has 16 divisors (see below), whose sum is σ = 20575724736. Its totient is φ = 8533693440.

The previous prime is 14113202399. The next prime is 14113202479. The reversal of 14113202433 is 33420231141.

It is a happy number.

It is not a de Polignac number, because 14113202433 - 213 = 14113194241 is a prime.

It is a super-3 number, since 3×141132024333 (a number of 31 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (14113202483) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 479560 + ... + 508137.

It is an arithmetic number, because the mean of its divisors is an integer number (1285982796).

Almost surely, 214113202433 is an apocalyptic number.

It is an amenable number.

14113202433 is a deficient number, since it is larger than the sum of its proper divisors (6462522303).

14113202433 is a wasteful number, since it uses less digits than its factorization.

14113202433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 988144.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 14113202433 its reverse (33420231141), we get a palindrome (47533433574).

The spelling of 14113202433 in words is "fourteen billion, one hundred thirteen million, two hundred two thousand, four hundred thirty-three".

Divisors: 1 3 11 33 433 1299 4763 14289 987697 2963091 10864667 32594001 427672801 1283018403 4704400811 14113202433