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1411322000000 = 27561164151
BaseRepresentation
bin10100100010011001010…
…110001011001010000000
311222220212110022222200012
4110202121112023022000
5141110341413000000
63000204040244052
7203651606031263
oct24423126131200
94886773288605
101411322000000
114a45a1526490
121a9634a70628
13a3119462b63
144c446178cda
1526aa2106735
hex1489958b280

1411322000000 has 224 divisors, whose sum is σ = 3834035298720. Its totient is φ = 513200000000.

The previous prime is 1411321999963. The next prime is 1411322000017. The reversal of 1411322000000 is 2231141.

It is a super-3 number, since 3×14113220000003 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 21967925 + ... + 22032075.

Almost surely, 21411322000000 is an apocalyptic number.

1411322000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1411322000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1917017649360).

1411322000000 is an abundant number, since it is smaller than the sum of its proper divisors (2422713298720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1411322000000 is an frugal number, since it uses more digits than its factorization.

1411322000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 64206 (or 64169 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 1411322000000 its reverse (2231141), we get a palindrome (1411324231141).

The spelling of 1411322000000 in words is "one trillion, four hundred eleven billion, three hundred twenty-two million", and thus it is an aban number.