1411322025 has 24 divisors (see below), whose sum is σ = 2366259264. Its totient is φ = 742100800.

The previous prime is 1411322023. The next prime is 1411322051. The reversal of 1411322025 is 5202231141.

It is not a de Polignac number, because 1411322025 - 2¹ = 1411322023 is a prime.

It is a super-3 number, since 3×1411322025³ (a number of 28 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1411321992 and 1411322010.

It is not an unprimeable number, because it can be changed into a prime (1411322023) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 127194 + ... + 137843.

It is an arithmetic number, because the mean of its divisors is an integer number (98594136).

Almost surely, 2^1411322025 is an apocalyptic number.

1411322025 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

It is an amenable number.

1411322025 is a deficient number, since it is larger than the sum of its proper divisors (954937239).

1411322025 is a wasteful number, since it uses less digits than its factorization.

1411322025 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 265121 (or 265116 counting only the distinct ones).

The product of its (nonzero) digits is 480, while the sum is 21.

The square root of 1411322025 is about 37567.5661309061. The cubic root of 1411322025 is about 1121.6965214221.

Adding to 1411322025 its reverse (5202231141), we get a palindrome (6613553166).

The spelling of 1411322025 in words is "one billion, four hundred eleven million, three hundred twenty-two thousand, twenty-five".