14113231122013 has 4 divisors (see below), whose sum is σ = 14114505925888. Its totient is φ = 14111956318140.

The previous prime is 14113231122007. The next prime is 14113231122047. The reversal of 14113231122013 is 31022113231141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14113231122013 - 2²¹ = 14113229024861 is a prime.

It is a super-3 number, since 3×14113231122013³ (a number of 40 digits) contains 333 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113231122073) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 637385331 + ... + 637407472.

It is an arithmetic number, because the mean of its divisors is an integer number (3528626481472).

Almost surely, 2^{14113231122013} is an apocalyptic number.

It is an amenable number.

14113231122013 is a deficient number, since it is larger than the sum of its proper divisors (1274803875).

14113231122013 is a wasteful number, since it uses less digits than its factorization.

14113231122013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1274803874.

The product of its (nonzero) digits is 864, while the sum is 25.

Adding to 14113231122013 its reverse (31022113231141), we get a palindrome (45135344353154).

The spelling of 14113231122013 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirty-one million, one hundred twenty-two thousand, thirteen".