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14113231122007 is a prime number
BaseRepresentation
bin1100110101011111111000…
…1000001010111001010111
31211222012201100020221021001
43031113332020022321113
53322212344131401012
650003310123004131
72654435011121563
oct315277610127127
954865640227231
1014113231122007
11455142a045566
1216bb2a4669647
137b4b44998264
1436b12681c6a3
151971b69e0357
hexcd5fe20ae57

14113231122007 has 2 divisors, whose sum is σ = 14113231122008. Its totient is φ = 14113231122006.

The previous prime is 14113231121939. The next prime is 14113231122047. The reversal of 14113231122007 is 70022113231141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14113231122007 is a prime.

It is a super-3 number, since 3×141132311220073 (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14113231122047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7056615561003 + 7056615561004.

It is an arithmetic number, because the mean of its divisors is an integer number (7056615561004).

Almost surely, 214113231122007 is an apocalyptic number.

14113231122007 is a deficient number, since it is larger than the sum of its proper divisors (1).

14113231122007 is an equidigital number, since it uses as much as digits as its factorization.

14113231122007 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 14113231122007 its reverse (70022113231141), we get a palindrome (84135344353148).

The spelling of 14113231122007 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirty-one million, one hundred twenty-two thousand, seven".