Base | Representation |
---|---|
bin | 1100110101100000101011… |
… | …1000000011100001110111 |
3 | 1211222020021020201010112122 |
4 | 3031120022320003201313 |
5 | 3322213313410020320 |
6 | 50003343243110155 |
7 | 2654443216063511 |
oct | 315301270034167 |
9 | 54866236633478 |
10 | 14113445001335 |
11 | 4551529848239 |
12 | 16bb34421235b |
13 | 7b4b7a0a1a84 |
14 | 36b146db4bb1 |
15 | 1971ca68bd25 |
hex | cd60ae03877 |
14113445001335 has 16 divisors (see below), whose sum is σ = 16960852560960. Its totient is φ = 11274280416000.
The previous prime is 14113445001287. The next prime is 14113445001343. The reversal of 14113445001335 is 53310054431141.
It is a happy number.
It is not a de Polignac number, because 14113445001335 - 228 = 14113176565879 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14113445001295 and 14113445001304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33227681 + ... + 33649749.
It is an arithmetic number, because the mean of its divisors is an integer number (1060053285060).
Almost surely, 214113445001335 is an apocalyptic number.
14113445001335 is a deficient number, since it is larger than the sum of its proper divisors (2847407559625).
14113445001335 is an equidigital number, since it uses as much as digits as its factorization.
14113445001335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 431818.
The product of its (nonzero) digits is 43200, while the sum is 35.
Adding to 14113445001335 its reverse (53310054431141), we get a palindrome (67423499432476).
The spelling of 14113445001335 in words is "fourteen trillion, one hundred thirteen billion, four hundred forty-five million, one thousand, three hundred thirty-five".
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