Base | Representation |
---|---|
bin | 1100110101100001011010… |
… | …1100010100101001001100 |
3 | 1211222020210001202022201222 |
4 | 3031120112230110221030 |
5 | 3322214220133033200 |
6 | 50003415044222512 |
7 | 2654451144144614 |
oct | 315302654245114 |
9 | 54866701668658 |
10 | 14113643252300 |
11 | 4551620746109 |
12 | 16bb39a69aa38 |
13 | 7b4bac195c37 |
14 | 36b16545da44 |
15 | 1971dcc9cd85 |
hex | cd616b14a4c |
14113643252300 has 36 divisors (see below), whose sum is σ = 30634284488640. Its totient is φ = 5644041885120.
The previous prime is 14113643252251. The next prime is 14113643252329. The reversal of 14113643252300 is 325234631141.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 17291804 + ... + 18089603.
Almost surely, 214113643252300 is an apocalyptic number.
14113643252300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14113643252300 is an abundant number, since it is smaller than the sum of its proper divisors (16520641236340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14113643252300 is a wasteful number, since it uses less digits than its factorization.
14113643252300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35385410 (or 35385403 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 14113643252300 its reverse (325234631141), we get a palindrome (14438877883441).
It can be divided in two parts, 1411364 and 3252300, that added together give a palindrome (4663664).
The spelling of 14113643252300 in words is "fourteen trillion, one hundred thirteen billion, six hundred forty-three million, two hundred fifty-two thousand, three hundred".
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