141142143134341 has 2 divisors, whose sum is σ = 141142143134342. Its totient is φ = 141142143134340.

The previous prime is 141142143134323. The next prime is 141142143134387. The reversal of 141142143134341 is 143431341241141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86756370776100 + 54385772358241 = 9314310^2 + 7374671^2 .

It is a cyclic number.

It is not a de Polignac number, because 141142143134341 - 2¹⁵ = 141142143101573 is a prime.

It is a super-2 number, since 2×141142143134341² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 141142143134341.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141142143194341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70571071567170 + 70571071567171.

It is an arithmetic number, because the mean of its divisors is an integer number (70571071567171).

Almost surely, 2^{141142143134341} is an apocalyptic number.

It is an amenable number.

141142143134341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141142143134341 is an equidigital number, since it uses as much as digits as its factorization.

141142143134341 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 55296, while the sum is 37.

Adding to 141142143134341 its reverse (143431341241141), we get a palindrome (284573484375482).

The spelling of 141142143134341 in words is "one hundred forty-one trillion, one hundred forty-two billion, one hundred forty-three million, one hundred thirty-four thousand, three hundred forty-one".