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14120023 is a prime number
BaseRepresentation
bin110101110111…
…010001010111
3222120101000211
4311313101113
512103320043
61222350251
7231006151
oct65672127
928511024
1014120023
117a74645
12488b387
132c04c58
141c37ad1
15138da9d
hexd77457

14120023 has 2 divisors, whose sum is σ = 14120024. Its totient is φ = 14120022.

The previous prime is 14120011. The next prime is 14120027. The reversal of 14120023 is 32002141.

14120023 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (32002141) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-14120023 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14119985 and 14120012.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14120027) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060011 + 7060012.

It is an arithmetic number, because the mean of its divisors is an integer number (7060012).

Almost surely, 214120023 is an apocalyptic number.

14120023 is a deficient number, since it is larger than the sum of its proper divisors (1).

14120023 is an equidigital number, since it uses as much as digits as its factorization.

14120023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 13.

The square root of 14120023 is about 3757.6619060261. The cubic root of 14120023 is about 241.7010115807.

Adding to 14120023 its reverse (32002141), we get a palindrome (46122164).

It can be divided in two parts, 141 and 20023, that added together give a square (20164 = 1422).

The spelling of 14120023 in words is "fourteen million, one hundred twenty thousand, twenty-three".