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141201103120000 = 275471122922257
BaseRepresentation
bin100000000110101111110001…
…100101111110011010000000
3200111221200201122122221201221
4200012233301211332122000
5122001414324344320000
61220150520303204424
741512304652251320
oct4006576145763200
9614850648587657
10141201103120000
1140a9a062673760
1213a058778a6714
1360a328c6cc221
1426c2254127280
15114ce70e7761a
hex806bf197e680

141201103120000 has 320 divisors, whose sum is σ = 438247900031040. Its totient is φ = 44010731520000.

The previous prime is 141201103119977. The next prime is 141201103120037. The reversal of 141201103120000 is 21301102141.

It is a tau number, because it is divible by the number of its divisors (320).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is an unprimeable number.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 5301129 + ... + 17621128.

It is an arithmetic number, because the mean of its divisors is an integer number (1369524687597).

Almost surely, 2141201103120000 is an apocalyptic number.

141201103120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141201103120000 is an abundant number, since it is smaller than the sum of its proper divisors (297046796911040).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141201103120000 is an equidigital number, since it uses as much as digits as its factorization.

141201103120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22922309 (or 22922282 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 141201103120000 its reverse (21301102141), we get a palindrome (141222404222141).

The spelling of 141201103120000 in words is "one hundred forty-one trillion, two hundred one billion, one hundred three million, one hundred twenty thousand".