141201304320343 has 4 divisors (see below), whose sum is σ = 142599337036488. Its totient is φ = 139803271604200.

The previous prime is 141201304320277. The next prime is 141201304320361. The reversal of 141201304320343 is 343023403102141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-141201304320343 is a prime.

It is a super-2 number, since 2×141201304320343² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141201304320743) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 699016357921 + ... + 699016358122.

It is an arithmetic number, because the mean of its divisors is an integer number (35649834259122).

Almost surely, 2^{141201304320343} is an apocalyptic number.

141201304320343 is a deficient number, since it is larger than the sum of its proper divisors (1398032716145).

141201304320343 is a wasteful number, since it uses less digits than its factorization.

141201304320343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1398032716144.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 141201304320343 its reverse (343023403102141), we get a palindrome (484224707422484).

The spelling of 141201304320343 in words is "one hundred forty-one trillion, two hundred one billion, three hundred four million, three hundred twenty thousand, three hundred forty-three".