Base | Representation |
---|---|
bin | 1100110101111010000010… |
… | …0111111011110010001111 |
3 | 1211222212211122220000002121 |
4 | 3031132200213323302033 |
5 | 3322321234043400012 |
6 | 50010430535433411 |
7 | 2655104005300303 |
oct | 315364047736217 |
9 | 54885748800077 |
10 | 14120252325007 |
11 | 4554402361274 |
12 | 1700723b25867 |
13 | 7b56c34b604a |
14 | 36b5d10d7d03 |
15 | 1974780e6a07 |
hex | cd7a09fbc8f |
14120252325007 has 2 divisors, whose sum is σ = 14120252325008. Its totient is φ = 14120252325006.
The previous prime is 14120252324989. The next prime is 14120252325041. The reversal of 14120252325007 is 70052325202141.
It is an a-pointer prime, because the next prime (14120252325041) can be obtained adding 14120252325007 to its sum of digits (34).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 14120252325007 - 223 = 14120243936399 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14120252325307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060126162503 + 7060126162504.
It is an arithmetic number, because the mean of its divisors is an integer number (7060126162504).
Almost surely, 214120252325007 is an apocalyptic number.
14120252325007 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120252325007 is an equidigital number, since it uses as much as digits as its factorization.
14120252325007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 33600, while the sum is 34.
Adding to 14120252325007 its reverse (70052325202141), we get a palindrome (84172577527148).
The spelling of 14120252325007 in words is "fourteen trillion, one hundred twenty billion, two hundred fifty-two million, three hundred twenty-five thousand, seven".
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