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141203323042147 is a prime number
BaseRepresentation
bin100000000110110001110101…
…111010010011100101100011
3200111221220110100211200102201
4200012301311322103211203
5122001433401144322042
61220151524443554031
741512413656263462
oct4006616572234543
9614856410750381
10141203323042147
1140a9aaa1770063
1213a0619722b917
1360a35545b7722
1426c23c4cac9d9
15114d050ccc1b7
hex806c75e93963

141203323042147 has 2 divisors, whose sum is σ = 141203323042148. Its totient is φ = 141203323042146.

The previous prime is 141203323041973. The next prime is 141203323042157. The reversal of 141203323042147 is 741240323302141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141203323042147 is a prime.

It is not a weakly prime, because it can be changed into another prime (141203323042157) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70601661521073 + 70601661521074.

It is an arithmetic number, because the mean of its divisors is an integer number (70601661521074).

Almost surely, 2141203323042147 is an apocalyptic number.

141203323042147 is a deficient number, since it is larger than the sum of its proper divisors (1).

141203323042147 is an equidigital number, since it uses as much as digits as its factorization.

141203323042147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 96768, while the sum is 37.

Adding to 141203323042147 its reverse (741240323302141), we get a palindrome (882443646344288).

The spelling of 141203323042147 in words is "one hundred forty-one trillion, two hundred three billion, three hundred twenty-three million, forty-two thousand, one hundred forty-seven".