Base | Representation |
---|---|
bin | 100000000110110010101010… |
… | …010011101001100111100111 |
3 | 200111221222201121221111210021 |
4 | 200012302222103221213213 |
5 | 122001442201214214343 |
6 | 1220152152005140011 |
7 | 41512444522204102 |
oct | 4006625223514747 |
9 | 614858647844707 |
10 | 141204202101223 |
11 | 40aa040299a168 |
12 | 13a063a16ba607 |
13 | 60a366475b621 |
14 | 26c2469937739 |
15 | 114d0a306e0ed |
hex | 806caa4e99e7 |
141204202101223 has 2 divisors, whose sum is σ = 141204202101224. Its totient is φ = 141204202101222.
The previous prime is 141204202101197. The next prime is 141204202101289. The reversal of 141204202101223 is 322101202402141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141204202101223 - 221 = 141204200004071 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141204202101623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70602101050611 + 70602101050612.
It is an arithmetic number, because the mean of its divisors is an integer number (70602101050612).
Almost surely, 2141204202101223 is an apocalyptic number.
141204202101223 is a deficient number, since it is larger than the sum of its proper divisors (1).
141204202101223 is an equidigital number, since it uses as much as digits as its factorization.
141204202101223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 141204202101223 its reverse (322101202402141), we get a palindrome (463305404503364).
The spelling of 141204202101223 in words is "one hundred forty-one trillion, two hundred four billion, two hundred two million, one hundred one thousand, two hundred twenty-three".
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