Base | Representation |
---|---|
bin | 10100100011000100010… |
… | …101110101100111001111 |
3 | 11222222201201122110012221 |
4 | 110203010111311213033 |
5 | 141113331043111142 |
6 | 3000403405040211 |
7 | 204005515200205 |
oct | 24430425654717 |
9 | 4888651573187 |
10 | 1412043332047 |
11 | 4a4931715977 |
12 | 1a97b6556067 |
13 | a3202a30a5a |
14 | 4c4b3ca7075 |
15 | 26ae55de767 |
hex | 148c45759cf |
1412043332047 has 2 divisors, whose sum is σ = 1412043332048. Its totient is φ = 1412043332046.
The previous prime is 1412043331883. The next prime is 1412043332081. The reversal of 1412043332047 is 7402333402141.
It is an a-pointer prime, because the next prime (1412043332081) can be obtained adding 1412043332047 to its sum of digits (34).
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1412043332047 - 235 = 1377683593679 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1412043335047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706021666023 + 706021666024.
It is an arithmetic number, because the mean of its divisors is an integer number (706021666024).
Almost surely, 21412043332047 is an apocalyptic number.
1412043332047 is a deficient number, since it is larger than the sum of its proper divisors (1).
1412043332047 is an equidigital number, since it uses as much as digits as its factorization.
1412043332047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48384, while the sum is 34.
Adding to 1412043332047 its reverse (7402333402141), we get a palindrome (8814376734188).
The spelling of 1412043332047 in words is "one trillion, four hundred twelve billion, forty-three million, three hundred thirty-two thousand, forty-seven".
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