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14120433354014 = 2132918727365191
BaseRepresentation
bin1100110101111010101101…
…1010100000010100011110
31211222220022021112020012122
43031132223122200110132
53322322121414312024
650010500523502542
72655111334102541
oct315365332402436
954886267466178
1014120433354014
114554495567019
121700774687a52
137b5721b5a3c0
1436b60b17c858
15197488e54d5e
hexcd7ab6a051e

14120433354014 has 16 divisors (see below), whose sum is σ = 23596480141920. Its totient is φ = 6292394703840.

The previous prime is 14120433354007. The next prime is 14120433354023. The reversal of 14120433354014 is 41045333402141.

It is a super-2 number, since 2×141204333540142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9363681842 + ... + 9363683349.

It is an arithmetic number, because the mean of its divisors is an integer number (1474780008870).

Almost surely, 214120433354014 is an apocalyptic number.

14120433354014 is a deficient number, since it is larger than the sum of its proper divisors (9476046787906).

14120433354014 is a wasteful number, since it uses less digits than its factorization.

14120433354014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 18727365235.

The product of its (nonzero) digits is 69120, while the sum is 35.

Adding to 14120433354014 its reverse (41045333402141), we get a palindrome (55165766756155).

The spelling of 14120433354014 in words is "fourteen trillion, one hundred twenty billion, four hundred thirty-three million, three hundred fifty-four thousand, fourteen".

Divisors: 1 2 13 26 29 58 377 754 18727365191 37454730382 243455747483 486911494966 543093590539 1086187181078 7060216677007 14120433354014