Base | Representation |
---|---|
bin | 11010010011010110… |
… | …01001001100010111 |
3 | 1100110010001111201201 |
4 | 31021223021030113 |
5 | 212404430323003 |
6 | 10253112533331 |
7 | 1006634040034 |
oct | 151153111427 |
9 | 40403044651 |
10 | 14120948503 |
11 | 5a969a8682 |
12 | 28a10b1247 |
13 | 14406a873c |
14 | 97d59c38b |
15 | 579a74b1d |
hex | 349ac9317 |
14120948503 has 2 divisors, whose sum is σ = 14120948504. Its totient is φ = 14120948502.
The previous prime is 14120948489. The next prime is 14120948551. The reversal of 14120948503 is 30584902141.
14120948503 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14120948503 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14120948563) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060474251 + 7060474252.
It is an arithmetic number, because the mean of its divisors is an integer number (7060474252).
Almost surely, 214120948503 is an apocalyptic number.
14120948503 is a deficient number, since it is larger than the sum of its proper divisors (1).
14120948503 is an equidigital number, since it uses as much as digits as its factorization.
14120948503 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 34560, while the sum is 37.
The spelling of 14120948503 in words is "fourteen billion, one hundred twenty million, nine hundred forty-eight thousand, five hundred three".
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