14121032531 has 2 divisors, whose sum is σ = 14121032532. Its totient is φ = 14121032530.

The previous prime is 14121032521. The next prime is 14121032533. The reversal of 14121032531 is 13523012141.

It is a strong prime.

It is an emirp because it is prime and its reverse (13523012141) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 14121032531 - 2⁶ = 14121032467 is a prime.

It is a super-2 number, since 2×14121032531² (a number of 21 digits) contains 22 as substring.

Together with 14121032533, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14121032497 and 14121032506.

It is not a weakly prime, because it can be changed into another prime (14121032533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060516265 + 7060516266.

It is an arithmetic number, because the mean of its divisors is an integer number (7060516266).

Almost surely, 2^14121032531 is an apocalyptic number.

14121032531 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121032531 is an equidigital number, since it uses as much as digits as its factorization.

14121032531 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14121032531 its reverse (13523012141), we get a palindrome (27644044672).

The spelling of 14121032531 in words is "fourteen billion, one hundred twenty-one million, thirty-two thousand, five hundred thirty-one".