141211022043317 has 2 divisors, whose sum is σ = 141211022043318. Its totient is φ = 141211022043316.

The previous prime is 141211022043239. The next prime is 141211022043319. The reversal of 141211022043317 is 713340220112141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 74618257370596 + 66592764672721 = 8638186^2 + 8160439^2 .

It is a cyclic number.

It is not a de Polignac number, because 141211022043317 - 2²⁶ = 141210954934453 is a prime.

It is a super-3 number, since 3×141211022043317³ (a number of 43 digits) contains 333 as substring.

Together with 141211022043319, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141211022043319) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70605511021658 + 70605511021659.

It is an arithmetic number, because the mean of its divisors is an integer number (70605511021659).

Almost surely, 2^{141211022043317} is an apocalyptic number.

It is an amenable number.

141211022043317 is a deficient number, since it is larger than the sum of its proper divisors (1).

141211022043317 is an equidigital number, since it uses as much as digits as its factorization.

141211022043317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

Adding to 141211022043317 its reverse (713340220112141), we get a palindrome (854551242155458).

The spelling of 141211022043317 in words is "one hundred forty-one trillion, two hundred eleven billion, twenty-two million, forty-three thousand, three hundred seventeen".