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14121201301 is a prime number
BaseRepresentation
bin11010010011011000…
…00110111010010101
31100110010112100111121
431021230012322111
5212410011420201
610253122203541
71006636142044
oct151154067225
940403470447
1014121201301
115a970605a9
1228a11b35b1
13144076681c
1497d62655b
15579ac49a1
hex349b06e95

14121201301 has 2 divisors, whose sum is σ = 14121201302. Its totient is φ = 14121201300.

The previous prime is 14121201271. The next prime is 14121201319. The reversal of 14121201301 is 10310212141.

14121201301 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10941369201 + 3179832100 = 104601^2 + 56390^2 .

It is a cyclic number.

It is not a de Polignac number, because 14121201301 - 29 = 14121200789 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14121201701) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7060600650 + 7060600651.

It is an arithmetic number, because the mean of its divisors is an integer number (7060600651).

Almost surely, 214121201301 is an apocalyptic number.

It is an amenable number.

14121201301 is a deficient number, since it is larger than the sum of its proper divisors (1).

14121201301 is an equidigital number, since it uses as much as digits as its factorization.

14121201301 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 14121201301 its reverse (10310212141), we get a palindrome (24431413442).

The spelling of 14121201301 in words is "fourteen billion, one hundred twenty-one million, two hundred one thousand, three hundred one".