Base | Representation |
---|---|
bin | 100000000110111001111101… |
… | …011111010100000000100011 |
3 | 200111222201221212120000220022 |
4 | 200012321331133110000203 |
5 | 122002104224232241212 |
6 | 1220155525441104055 |
7 | 41513142665225624 |
oct | 4006717537240043 |
9 | 614881855500808 |
10 | 141212040118307 |
11 | 40aa3765290434 |
12 | 13a07a0a62802b |
13 | 60a4313568562 |
14 | 26c29b08b7a4b |
15 | 114d3b121e772 |
hex | 806e7d7d4023 |
141212040118307 has 2 divisors, whose sum is σ = 141212040118308. Its totient is φ = 141212040118306.
The previous prime is 141212040118297. The next prime is 141212040118309. The reversal of 141212040118307 is 703811040212141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 141212040118307 - 216 = 141212040052771 is a prime.
Together with 141212040118309, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (141212040118309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70606020059153 + 70606020059154.
It is an arithmetic number, because the mean of its divisors is an integer number (70606020059154).
Almost surely, 2141212040118307 is an apocalyptic number.
141212040118307 is a deficient number, since it is larger than the sum of its proper divisors (1).
141212040118307 is an equidigital number, since it uses as much as digits as its factorization.
141212040118307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 10752, while the sum is 35.
The spelling of 141212040118307 in words is "one hundred forty-one trillion, two hundred twelve billion, forty million, one hundred eighteen thousand, three hundred seven".
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