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1412124005335 = 52671105737477
BaseRepresentation
bin10100100011001001001…
…001100101001111010111
311222222221100110002011111
4110203021021211033113
5141114012221132320
63000415410115451
7204010514666251
oct24431111451727
94888840402144
101412124005335
114a4973206a0a
121a981957bb87
13a3216668724
144c4c08a6cd1
1526aec727a5a
hex148c92653d7

1412124005335 has 8 divisors (see below), whose sum is σ = 1695183247296. Its totient is φ = 1129276243680.

The previous prime is 1412124005329. The next prime is 1412124005381. The reversal of 1412124005335 is 5335004212141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1412124005335 - 217 = 1412123874263 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412124005297 and 1412124005306.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 52855384 + ... + 52882093.

It is an arithmetic number, because the mean of its divisors is an integer number (211897905912).

Almost surely, 21412124005335 is an apocalyptic number.

1412124005335 is a deficient number, since it is larger than the sum of its proper divisors (283059241961).

1412124005335 is a wasteful number, since it uses less digits than its factorization.

1412124005335 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 105740153.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1412124005335 its reverse (5335004212141), we get a palindrome (6747128217476).

The spelling of 1412124005335 in words is "one trillion, four hundred twelve billion, one hundred twenty-four million, five thousand, three hundred thirty-five".

Divisors: 1 5 2671 13355 105737477 528687385 282424801067 1412124005335