Base | Representation |
---|---|
bin | 11010010011011001… |
… | …10111101111011111 |
3 | 1100110010220111212101 |
4 | 31021230313233133 |
5 | 212410034320221 |
6 | 10253130345531 |
7 | 1006640634133 |
oct | 151154675737 |
9 | 40403814771 |
10 | 14121401311 |
11 | 5a971878a6 |
12 | 28a128b2a7 |
13 | 1440806884 |
14 | 97d6793c3 |
15 | 579b13d91 |
hex | 349b37bdf |
14121401311 has 4 divisors (see below), whose sum is σ = 14139670392. Its totient is φ = 14103132232.
The previous prime is 14121401233. The next prime is 14121401347. The reversal of 14121401311 is 11310412141.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14121401311 - 213 = 14121393119 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14121401351) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9133381 + ... + 9134926.
It is an arithmetic number, because the mean of its divisors is an integer number (3534917598).
Almost surely, 214121401311 is an apocalyptic number.
14121401311 is a deficient number, since it is larger than the sum of its proper divisors (18269081).
14121401311 is an equidigital number, since it uses as much as digits as its factorization.
14121401311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 18269080.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 14121401311 its reverse (11310412141), we get a palindrome (25431813452).
The spelling of 14121401311 in words is "fourteen billion, one hundred twenty-one million, four hundred one thousand, three hundred eleven".
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