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1412142150541 is a prime number
BaseRepresentation
bin10100100011001010001…
…110110011001110001101
311222222222121120221201011
4110203022032303032031
5141114031342304131
63000421255045221
7204011125141603
oct24431216631615
94888877527634
101412142150541
114a498247a751
121a9823670811
13a321a34c835
144c4c306b873
1526aee10e0b1
hex148ca3b338d

1412142150541 has 2 divisors, whose sum is σ = 1412142150542. Its totient is φ = 1412142150540.

The previous prime is 1412142150527. The next prime is 1412142150571. The reversal of 1412142150541 is 1450512412141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1158322672516 + 253819478025 = 1076254^2 + 503805^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412142150541 - 27 = 1412142150413 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412142150511) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706071075270 + 706071075271.

It is an arithmetic number, because the mean of its divisors is an integer number (706071075271).

Almost surely, 21412142150541 is an apocalyptic number.

It is an amenable number.

1412142150541 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412142150541 is an equidigital number, since it uses as much as digits as its factorization.

1412142150541 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6400, while the sum is 31.

Adding to 1412142150541 its reverse (1450512412141), we get a palindrome (2862654562682).

The spelling of 1412142150541 in words is "one trillion, four hundred twelve billion, one hundred forty-two million, one hundred fifty thousand, five hundred forty-one".