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141217131941 is a prime number
BaseRepresentation
bin1000001110000100110…
…0100110110110100101
3111111111122221120212222
42003201030212312211
54303203041210231
6144512501122125
713126330546634
oct2034114466645
9444448846788
10141217131941
1154987431406
12234513b9345
1310416aa4302
146b9913b51b
153a179e327b
hex20e1326da5

141217131941 has 2 divisors, whose sum is σ = 141217131942. Its totient is φ = 141217131940.

The previous prime is 141217131893. The next prime is 141217131947. The reversal of 141217131941 is 149131712141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 120055320100 + 21161811841 = 346490^2 + 145471^2 .

It is a cyclic number.

It is not a de Polignac number, because 141217131941 - 230 = 140143390117 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141217131947) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70608565970 + 70608565971.

It is an arithmetic number, because the mean of its divisors is an integer number (70608565971).

Almost surely, 2141217131941 is an apocalyptic number.

It is an amenable number.

141217131941 is a deficient number, since it is larger than the sum of its proper divisors (1).

141217131941 is an equidigital number, since it uses as much as digits as its factorization.

141217131941 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6048, while the sum is 35.

The spelling of 141217131941 in words is "one hundred forty-one billion, two hundred seventeen million, one hundred thirty-one thousand, nine hundred forty-one".