14122043412432 has 20 divisors (see below), whose sum is σ = 36481945482240. Its totient is φ = 4707347804128.

The previous prime is 14122043412401. The next prime is 14122043412473. The reversal of 14122043412432 is 23421434022141.

It is a super-2 number, since 2×14122043412432² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 14122043412393 and 14122043412402.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 147104618832 + ... + 147104618927.

It is an arithmetic number, because the mean of its divisors is an integer number (1824097274112).

Almost surely, 2^{14122043412432} is an apocalyptic number.

14122043412432 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

14122043412432 is an abundant number, since it is smaller than the sum of its proper divisors (22359902069808).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14122043412432 is a wasteful number, since it uses less digits than its factorization.

14122043412432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 294209237770 (or 294209237764 counting only the distinct ones).

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 14122043412432 its reverse (23421434022141), we get a palindrome (37543477434573).

The spelling of 14122043412432 in words is "fourteen trillion, one hundred twenty-two billion, forty-three million, four hundred twelve thousand, four hundred thirty-two".