141221020433 has 4 divisors (see below), whose sum is σ = 149528139300. Its totient is φ = 132913901568.

The previous prime is 141221020427. The next prime is 141221020463. The reversal of 141221020433 is 334020122141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334020122141 = 191 ⋅1748796451.

It can be written as a sum of positive squares in 2 ways, for example, as 91245076624 + 49975943809 = 302068^2 + 223553^2 .

It is a cyclic number.

It is not a de Polignac number, because 141221020433 - 2⁴ = 141221020417 is a prime.

It is a super-2 number, since 2×141221020433² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 141221020399 and 141221020408.

It is not an unprimeable number, because it can be changed into a prime (141221020463) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4153559408 + ... + 4153559441.

It is an arithmetic number, because the mean of its divisors is an integer number (37382034825).

Almost surely, 2^141221020433 is an apocalyptic number.

It is an amenable number.

141221020433 is a deficient number, since it is larger than the sum of its proper divisors (8307118867).

141221020433 is an equidigital number, since it uses as much as digits as its factorization.

141221020433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8307118866.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 141221020433 its reverse (334020122141), we get a palindrome (475241142574).

The spelling of 141221020433 in words is "one hundred forty-one billion, two hundred twenty-one million, twenty thousand, four hundred thirty-three".