Base | Representation |
---|---|
bin | 11010010011011111… |
… | …01010011010000010 |
3 | 1100110012021200201111 |
4 | 31021233222122002 |
5 | 212410231224442 |
6 | 10253154153534 |
7 | 1006650102526 |
oct | 151157523202 |
9 | 40405250644 |
10 | 14122133122 |
11 | 5a976376a9 |
12 | 28a15828aa |
13 | 1440a019b6 |
14 | 97d7c9d86 |
15 | 579c0ab17 |
hex | 349bea682 |
14122133122 has 4 divisors (see below), whose sum is σ = 21183199686. Its totient is φ = 7061066560.
The previous prime is 14122133083. The next prime is 14122133149. The reversal of 14122133122 is 22133122141.
14122133122 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22133122141 = 13 ⋅1702547857.
It can be written as a sum of positive squares in only one way, i.e., 7572306361 + 6549826761 = 87019^2 + 80931^2 .
It is a junction number, because it is equal to n+sod(n) for n = 14122133093 and 14122133102.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3530533279 + ... + 3530533282.
Almost surely, 214122133122 is an apocalyptic number.
14122133122 is a deficient number, since it is larger than the sum of its proper divisors (7061066564).
14122133122 is an equidigital number, since it uses as much as digits as its factorization.
14122133122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7061066563.
The product of its digits is 576, while the sum is 22.
Adding to 14122133122 its reverse (22133122141), we get a palindrome (36255255263).
The spelling of 14122133122 in words is "fourteen billion, one hundred twenty-two million, one hundred thirty-three thousand, one hundred twenty-two".
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