14122211222141 has 4 divisors (see below), whose sum is σ = 15406048605984. Its totient is φ = 12838373838300.

The previous prime is 14122211222137. The next prime is 14122211222221.

14122211222141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14122211222141 - 2² = 14122211222137 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 14122211222141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14122211222741) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641918691905 + ... + 641918691926.

It is an arithmetic number, because the mean of its divisors is an integer number (3851512151496).

Almost surely, 2^{14122211222141} is an apocalyptic number.

14122211222141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14122211222141 is a deficient number, since it is larger than the sum of its proper divisors (1283837383843).

14122211222141 is a wasteful number, since it uses less digits than its factorization.

14122211222141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1283837383842.

The product of its digits is 1024, while the sum is 26.

It can be divided in two parts, 1412221 and 1222141, that added together give a palindrome (2634362).

The spelling of 14122211222141 in words is "fourteen trillion, one hundred twenty-two billion, two hundred eleven million, two hundred twenty-two thousand, one hundred forty-one".