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141222221431 is a prime number
BaseRepresentation
bin1000001110000110000…
…0000001011001110111
3111111112000112011100121
42003201200001121313
54303210342041211
6144513202152411
713126422035044
oct2034140013167
9444460464317
10141222221431
115498a2981a5
1223453052707
1310417b66a45
146b99aa41cb
153a1819b271
hex20e1801677

141222221431 has 2 divisors, whose sum is σ = 141222221432. Its totient is φ = 141222221430.

The previous prime is 141222221429. The next prime is 141222221471. The reversal of 141222221431 is 134122222141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 141222221431 - 21 = 141222221429 is a prime.

It is a super-2 number, since 2×1412222214312 (a number of 23 digits) contains 22 as substring.

Together with 141222221429, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 141222221396 and 141222221405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141222221471) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70611110715 + 70611110716.

It is an arithmetic number, because the mean of its divisors is an integer number (70611110716).

Almost surely, 2141222221431 is an apocalyptic number.

141222221431 is a deficient number, since it is larger than the sum of its proper divisors (1).

141222221431 is an equidigital number, since it uses as much as digits as its factorization.

141222221431 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1536, while the sum is 25.

Adding to 141222221431 its reverse (134122222141), we get a palindrome (275344443572).

The spelling of 141222221431 in words is "one hundred forty-one billion, two hundred twenty-two million, two hundred twenty-one thousand, four hundred thirty-one".