1412300032141 has 4 divisors (see below), whose sum is σ = 1486631612800. Its totient is φ = 1337968451484.

The previous prime is 1412300032093. The next prime is 1412300032189.

1412300032141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (1412300032093) and next prime (1412300032189).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1412300032141 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412300032541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37165790301 + ... + 37165790338.

It is an arithmetic number, because the mean of its divisors is an integer number (371657903200).

Almost surely, 2^{1412300032141} is an apocalyptic number.

It is an amenable number.

1412300032141 is a deficient number, since it is larger than the sum of its proper divisors (74331580659).

1412300032141 is an equidigital number, since it uses as much as digits as its factorization.

1412300032141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74331580658.

The product of its (nonzero) digits is 576, while the sum is 22.

It can be divided in two parts, 14123000 and 32141, that added together give a palindrome (14155141).

The spelling of 1412300032141 in words is "one trillion, four hundred twelve billion, three hundred million, thirty-two thousand, one hundred forty-one".