1412400113 has 2 divisors, whose sum is σ = 1412400114. Its totient is φ = 1412400112.

The previous prime is 1412400097. The next prime is 1412400167. The reversal of 1412400113 is 3110042141.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1297224289 + 115175824 = 36017^2 + 10732^2 .

It is a cyclic number.

It is not a de Polignac number, because 1412400113 - 2⁴ = 1412400097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1412400091 and 1412400100.

It is not a weakly prime, because it can be changed into another prime (1412400173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706200056 + 706200057.

It is an arithmetic number, because the mean of its divisors is an integer number (706200057).

Almost surely, 2^1412400113 is an apocalyptic number.

It is an amenable number.

1412400113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412400113 is an equidigital number, since it uses as much as digits as its factorization.

1412400113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 17.

The square root of 1412400113 is about 37581.9120455572. The cubic root of 1412400113 is about 1121.9820645157.

Adding to 1412400113 its reverse (3110042141), we get a palindrome (4522442254).

The spelling of 1412400113 in words is "one billion, four hundred twelve million, four hundred thousand, one hundred thirteen".