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1412401114303 = 3998335325041
BaseRepresentation
bin10100100011011001101…
…010101010110010111111
312000000122122212200012121
4110203121222222302333
5141120044141124203
63000503105343411
7204020421246154
oct24433152526277
95000578780177
101412401114303
114a4aa5675a93
121a9896337b67
13a325bbb022a
144c5095dc22b
1526b16c140bd
hex148d9aaacbf

1412401114303 has 4 divisors (see below), whose sum is σ = 1412436479328. Its totient is φ = 1412365749280.

The previous prime is 1412401114259. The next prime is 1412401114321. The reversal of 1412401114303 is 3034111042141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1412401114303 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412401114903) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 17622538 + ... + 17702503.

It is an arithmetic number, because the mean of its divisors is an integer number (353109119832).

Almost surely, 21412401114303 is an apocalyptic number.

1412401114303 is a deficient number, since it is larger than the sum of its proper divisors (35365025).

1412401114303 is an equidigital number, since it uses as much as digits as its factorization.

1412401114303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 35365024.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 1412401114303 its reverse (3034111042141), we get a palindrome (4446512156444).

The spelling of 1412401114303 in words is "one trillion, four hundred twelve billion, four hundred one million, one hundred fourteen thousand, three hundred three".

Divisors: 1 39983 35325041 1412401114303