141240421433 has 4 divisors (see below), whose sum is σ = 142056840228. Its totient is φ = 140424002640.

The previous prime is 141240421423. The next prime is 141240421459. The reversal of 141240421433 is 334124042141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 334124042141 = 23 ⋅14527132267.

It can be written as a sum of positive squares in 2 ways, for example, as 86340182569 + 54900238864 = 293837^2 + 234308^2 .

It is a cyclic number.

It is not a de Polignac number, because 141240421433 - 2⁴ = 141240421417 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141240421396 and 141240421405.

It is not an unprimeable number, because it can be changed into a prime (141240421423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 408209138 + ... + 408209483.

It is an arithmetic number, because the mean of its divisors is an integer number (35514210057).

Almost surely, 2^141240421433 is an apocalyptic number.

It is an amenable number.

141240421433 is a deficient number, since it is larger than the sum of its proper divisors (816418795).

141240421433 is an equidigital number, since it uses as much as digits as its factorization.

141240421433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 816418794.

The product of its (nonzero) digits is 9216, while the sum is 29.

Adding to 141240421433 its reverse (334124042141), we get a palindrome (475364463574).

The spelling of 141240421433 in words is "one hundred forty-one billion, two hundred forty million, four hundred twenty-one thousand, four hundred thirty-three".