Base | Representation |
---|---|
bin | 11010010011101101… |
… | …11110111111010011 |
3 | 1100110022220012112011 |
4 | 31021312332333103 |
5 | 212411224134220 |
6 | 10253303243351 |
7 | 1010002315303 |
oct | 151166767723 |
9 | 40408805464 |
10 | 14124052435 |
11 | 5a98728709 |
12 | 28a2149557 |
13 | 144122449c |
14 | 97db69603 |
15 | 579e8965a |
hex | 349dbefd3 |
14124052435 has 8 divisors (see below), whose sum is σ = 16951463280. Its totient is φ = 11297508384.
The previous prime is 14124052417. The next prime is 14124052447. The reversal of 14124052435 is 53425042141.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14124052435 - 29 = 14124051923 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 14124052397 and 14124052406.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 180292 + ... + 246481.
It is an arithmetic number, because the mean of its divisors is an integer number (2118932910).
Almost surely, 214124052435 is an apocalyptic number.
14124052435 is a deficient number, since it is larger than the sum of its proper divisors (2827410845).
14124052435 is an equidigital number, since it uses as much as digits as its factorization.
14124052435 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 433397.
The product of its (nonzero) digits is 19200, while the sum is 31.
Adding to 14124052435 its reverse (53425042141), we get a palindrome (67549094576).
The spelling of 14124052435 in words is "fourteen billion, one hundred twenty-four million, fifty-two thousand, four hundred thirty-five".
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