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14124333505 = 52824866701
BaseRepresentation
bin11010010011110000…
…00011100111000001
31100110100102111002011
431021320003213001
5212411312133010
610253313252521
71010004565612
oct151170034701
940410374064
1014124333505
115a988aa8a7
1228a2264141
1314412c23b9
1497dbddc09
15579ee2a8a
hex349e039c1

14124333505 has 4 divisors (see below), whose sum is σ = 16949200212. Its totient is φ = 11299466800.

The previous prime is 14124333493. The next prime is 14124333521. The reversal of 14124333505 is 50533342141.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 8924769841 + 5199563664 = 94471^2 + 72108^2 .

It is not a de Polignac number, because 14124333505 - 25 = 14124333473 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412433346 + ... + 1412433355.

It is an arithmetic number, because the mean of its divisors is an integer number (4237300053).

Almost surely, 214124333505 is an apocalyptic number.

It is an amenable number.

14124333505 is a deficient number, since it is larger than the sum of its proper divisors (2824866707).

14124333505 is an equidigital number, since it uses as much as digits as its factorization.

14124333505 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2824866706.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 14124333505 its reverse (50533342141), we get a palindrome (64657675646).

The spelling of 14124333505 in words is "fourteen billion, one hundred twenty-four million, three hundred thirty-three thousand, five hundred five".

Divisors: 1 5 2824866701 14124333505